**OPSC AEE 2019 Answer Key:-** Odisha Public Service Commission (OPSC) has successfully conducted a written examination of Assistant Executive Engineer **(AEE) on 15 Dec 2019**. We have arranged the OPSC Civil Engg question paper and its answer key with the help of Made Easy.

**OPSC Civil Engineer Question Paper-I consists of: **

Civil Engg Topics/Sections |
No. of Questions |
Total Marks |

Solid Mechanics | 40 | 40 |

Structural Analysis | 40 | 40 |

Design Of Concrete Structure | 30 | 30 |

Design Of Steel Structure | 20 | 20 |

Building Material and Building Structure | 30 | 30 |

Estimation, Construction Planning nd Management | 20 | 20 |

Total |
180 |
180 |

**Question paper marking criteria:** The questions will be of Multiple Choice Questions (MCQ) type only. Each correct/right answer will be awarded 1 marks each and there will be 0.25 negative marks for each wrong answer.

Below is the **OPSC AEE 2019 Civil Engg question paper** – 1 along with answers and solved paper.

## OPSC 2019 Civil Engg Paper-1 Answer Key: (SET A)

- Strain energy per unit volume that a material can absorb without exceeding its proportional limit is called:
- Strain hardening
- Shear modulus of material
- Bulk modulus of material
**Modulus of resilience**

- The Lueders ‘ Lines in a material indicate that:
- The material is failing in flexure
- The material is failing due to fatigue
- The material is failing due to its crushing
**The material is failing in shear**

- For structural steel, experiment indicates, the value of Poison’s ratio (µ) is
- 1.3
- 0.01
- 0.75
**0.3**

- A prismatic bar is subjected to axial tension. What is the aspect angle (theta) which defines as oblique section on which normal and shearing stresses are equal?
- 30 degree
**45**degree- 60 degree
- 90 degree

- What is the total elongation of a prismatic bar of length (L) and cross-sectional area (A) and Young ‘s Modulus of its material (E) hangs vertically under its own weight (W)?
**WL/2AE**- WL/8AE
- WL/6AE
- WL/4AE

- Select in which case of the following biaxial stress, pure shear condition prevails:
- IMG

- A steel wire of 20 mm diameter is bent into a circular shape of 10 m radius, then the maximum stress induced in the wire is
- IMG

- The ratio of width to depth of a strongest beam that can be cut out of a cylindrical log of wood with homogeneous and isotropic properties is
- IMG

- The maximum shear stress caused due to a shear force in a beam of rectangular cross-section is how much more is percentage than its average value?
- 200%
- 150%
- 100%
**50%**

- The diameter of the core of solid circular column of diameter “D”, where stress induced due to a normal concentrated load of any eccentricity with respect to the centre of the column is:
- 0.20 D
**0.25 D**- 0.33 D
- 0.5 D

- A beam of rectangular cross-section is 100 mm wide and 200 mm deep. If the section is subjected to a shear force of 20 kN, then the maximum shear stress in the section is:
- 1.25 N/mm2
**1.5 N/mm2**- 1.6 N/mm2
- 1.75 N/mm2

- For no torsion, the plane of bending should
- Be parallel to one of the principal axes
**Pass through shear centre of section**- Pass through neutral axis of the section
- Pass through centre of gravity of the section

- Two beams, one of circular cross-section and other of square of cross-section, have equal areas of cross-section. If subjected to bending
- Circular section is more economical
**Square section is more economical**- Both sections are equally strong
- Both sections are equally stiff

- A simply supported beam with rectangular cross-section is subjected to a central concentrated load. If the width and depth of the beam are doubled , then the deflection at the centre of the beam will be reduced to:
- 50%
- 25%
- 12.5%
**6.25%**

- If the deflection at the free end of a uniformly loaded cantilever beam is 15 mm and the slope of the deflection curve at the free end is 0.02 radian, then the length of the beam is:
- 0.8 m
**1.0 m**- 1.2 m
- 1.5 m

- Two ratio of maximum shear stress developed in a solid shaft of diameter D and a hollow shaft of external diameter D and internal diameter d for the same torque is given by
- IMG

- Strain energy stored in a member is given by:
- 0.5 x stress x strain
- 0.5 x strain x volume
- 0.5 x stress x volume
**0.5 x stress x strain x volume**

- In-plane stress problem there are normal tensile stresses0 x and0 Y accompanied by shear stress 1x:y at a point along with orthogonal Cartesian coordinates X and Y respectively, If it observed that the minimum principle stress on a certain plane is zero then:

IMG - If the depth of a rectangular section is reduced to half, strain energy stored in the beam becomes:
- ¼ times
- 1/8 times
- 4 times
**8 times**

- The phenomenon of decreased resistance of a material to reversal of stress is called
- Creep
**Fatigue**- Resilience
- Plasticity

- The property of a metal which allows it to deform continuously at a slow rate without any further increase in stress is known as:
- Fatigue
**Creep**- Plasticity
- Resilience

- If a circular shaft is subjected to a torque T and bending moment M, the ratio of maximum bending stress to maximum shear stress is:
**2M/T**- M/2T
- M/T
- 2T/M

- The identical bars, one simply supported and other fixed at ends, are acted upon by equal loads applied at the midpoint s. The ratio of strain energy stored in the simply supported beam and the fixed ended beam is:
- 1
- 2
- 3
- 4

- For ductile materials, the most appropriate failure theory is :
- Maximum shear stress theory
- Maximum principal stress theory
- Maximum principal strain theory
**Shear strain energy theory**

- The stress below which a material has a high probability of not failing under reversal of stress is known as:
- Tolerance limit
- Elastic limit
- Proportional limit
**Endurance limit**

- In terms of bulk modulus (K) and modulus of rigidity (G) , the Poisson ‘s ratio can be expressed as:
- (3K – 4G) / (6K + 4G)
- (3K + 4G) / (6K – 4G)
**(3K – 2G) / (6K + 2G)**- (3K + 2G) / (6K – 2G)

- The deflection at the free end of a cantilever subjected to a couple of Mat its free end having a uniform flexural rigidity El throughout its length “L” is equal to
- IMG

- The shear centre of a section is defined as that point:
**Through which load must be applied to produce zero twisting moment on the section**- At which shear force is zero
- At which shear force is maximum
- At which shear force is minimum

- If a three hinged parabolic arch carries a uniformly distributed load over the entire span, then any section of the arch is subjected to:
**Normal thrust only**- Normal thrust and shear force
- Normal thrust and bending moment
- Normal thrust, bending moment and shear force

- If the area under the shear force diagram for a beam between the two points C and Dis “K”, then the difference between the moments at the two points C and D will be equal to:
**K**- 2K
- K / 2
- K
^{2}

- Given that for an element in a body of homogeneous isotropic material subjected to plane stress;xe ,ye and ze are normal strains in x, y and z directions respectively and µ is the Poisson’s ratio, the magnitude of unit volume change of the element is given by:
- Img

- If a material has identical properties in all directions, it is said to be:
- Homogeneous
- Orthotropic
- Elastic
**Isotropic**

- If the Young’s modulus of elasticity of a material is twice its modulus of rigidity , then the Poisson ‘s ratio of the material is:
**Zero**- 0.5
- – 0.5
- – 1

- If a composite bar of steel and copper is heated, then the copper bar will be under:
- Tension
**Compression**- Shear
- Torsion

- Shear stress on principal planes is:
**Zero**- Maximum
- Minimum
- Depends on axial force

- A simply supported beam of span L carries over its full span of load varying linearly from zero at either end to w/unit length at midspan . The maximum bending moment occurs at
**Quarter points and is equal to wL**^{2 }/ 8- Quarter points and is equal to wL
^{2 }/ 12 - Midspan and is equal to wL
^{2 }/ 8 - Midspan and is equal to wL
^{2 }/ 12

- Consider the following statements about flitched beams:
- A flitched beam has a composite section made of two or more materials joined together in such a manner that they behave as a unit piece and each material bends to the same radius of curv ature.
- The total moment of resistance of a flitched beam is equal to the sum of the moments of resistance of individual sections .
- Flitched beams are used when a beam of one materia,lif used alone, would require quite a large cross-sectional area.
**1, 2 and 3 are correct**- 1 and 3 are correct
- 2 and 3 are correct
- 1 and 2 are correct

- Consider the following statements:

The theory of simple bending assumes that:- The material of the beam is homogeneous, isotropic and obeys Hooke’s law.
- The plane section remains plane after bending.
- Each cross-section of the beam is symmetric about the loading plane.
- Young’s moduli are the same in tension and compression.

Of the above statements which are correct?**1 and 2 only** - 1, 3 and 4 only
- 2, 3 and 4 only
- 1, 2, 3 and 4

- If the diameter of a shaft, subjected to a torque alone, is doubled, then the horse power “P” can be increased to:
- 16P

- 8P

- 4P

- 2P

- A flitched beam consists of a wooden joist 150 mm wide and 300 mm deep strengthened by steel plates 10 mm thick and 300 mm deep one on either side of the joist. If the modulus of elasticity of steel is 20 times that of wood, then the width of equivalent wooden section will be:
- 150 mm

- 350 mm

- 500 mm

**550 mm**

- Find out the wrong statement from the followings:
**The elastic section modulus of a section does not affect Shape Factor.**

- The Shape Factor is a function of the cross sectional shape.

- The Shape Factor represents the increase of strength due to pla sticization .

- The Shape Factor of a section is a measure of reserve strength available in the section after initial yielding.

- Find the correct statement with regards to Plastic Hinge :
- Plastic Hinges are reached first at sections subjected to least curvature

- The plastic hinge will not form at the point of zero shear in a span under distributed load

**Where three structural members meets, plastic hinge will form in all members irrespective of their capacities of taking the moment**

- A plastic hinge is a zone of yielding due to shear in a structural member.

- Choose the correct statement:
- Through equilibrium condition will always be satisfied , a solution arrived at on the basis of an assumed mechanism will give a loading that is either correct or too high.

- The load obtained using the assumed moment diagram that does not violate the plastic moment condition will be either correct or too high.

**The strain at the onset of strain hardening is about 30 to 40 times the elastic strain in structural steel.**

- The load factor of a rectangular steel section is 3.75, if the Factor of safety is 1.65.

- A fixed beam of 8 meters length is subjected to a single central concentrated load. If the plastic moment value is Mp, the ultimate load by mechanism method is:
**Mp**

- 2Mp

- 1.5Mp

- 4Mp

- How many independent mechanisms can be formed for a symmetrical portal frame of single bay and single storied, statically indeterminate to first degree and subjected to a concentrated load on the beam portion and one at the beam column junction?
- 1

- 4

- 3

**2**

- What is the value of kinematic indeterminacy and statical indeterminacy of respectively?
- 3, 1

- 1, 2

- 2, 0

**0, 3**

- What is the value of Bending Moment in kN-m at 3 m from the left support of a three-hinged parabolic arch of span 10 m and rise 4 m which carries a uniformly distributed load of 5 kN/m over the whole span?
- 27.5

- 120

**0**

- 225

- Which method of structural analysis is a Force Method of analysis?
- Moment distribution method

- Slope deflection method

**None of these**

- Both of these

- How many simultaneous equations, you have to solve to find the support moments for a continuous two spanned beams ABC of two consecutive spans AB and BC of equal length carrying uniformly distributed loads of 5 kN/m with end supports are simple supported?
- 4

- 6

**1**

- 3

- The stiffness of a member of length (L), moment of inertia of the section of the member is (I) and Young’s Modulus of the material of the member is (E) is:
- 3EI / L
^{2}

**4EI / L**

- 2EI / L

- 4EI / L
^{2}

- 3EI / L

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